f(x) = sin x として，-π ≦ x ≦ 2π まで，有名な値を表にする。
| x |
-π |
… |
\(-\dfrac{5}{6}\pi\) |
… |
\(-\dfrac{3}{4}\pi\) |
… |
\(-\dfrac{2}{3}\pi\) |
… |
\(-\dfrac{\pi}{2}\) |
… |
\(-\dfrac{\pi}{3}\) |
… |
\(-\dfrac{\pi}{4}\) |
… |
\(-\dfrac{\pi}{6}\) |
… |
0 |
| sin x |
0 |
↘ |
\(-\dfrac{1}{2}\) |
↘ |
\(-\dfrac{\sqrt{2}}{2}\) |
↘ |
\(-\dfrac{\sqrt{3}}{2}\) |
↘ |
-1 |
↗ |
\(-\dfrac{\sqrt{3}}{2}\) |
↗ |
\(-\dfrac{\sqrt{2}}{2}\) |
↗ |
\(-\dfrac{1}{2}\) |
↗ |
0 |
| x |
0 |
… |
\(\dfrac{\pi}{6}\) |
… |
\(\dfrac{\pi}{4}\) |
… |
\(\dfrac{\pi}{3}\) |
… |
\(\dfrac{\pi}{2}\) |
… |
\(\dfrac{2}{3}\pi\) |
… |
\(\dfrac{3}{4}\pi\) |
… |
\(\dfrac{5}{6}\pi\) |
… |
π |
| sin x |
0 |
↗ |
\(\dfrac{1}{2}\) |
↗ |
\(\dfrac{\sqrt{2}}{2}\) |
↗ |
\(\dfrac{\sqrt{3}}{2}\) |
↗ |
1 |
↘ |
\(\dfrac{\sqrt{3}}{2}\) |
↘ |
\(\dfrac{\sqrt{2}}{2}\) |
↘ |
\(\dfrac{1}{2}\) |
↘ |
0 |
| x |
π |
… |
\(\dfrac{7}{6}\pi\) |
… |
\(\dfrac{5}{4}\pi\) |
… |
\(\dfrac{4}{3}\pi\) |
… |
\(\dfrac{3}{2}\pi\) |
… |
\(\dfrac{5}{3}\pi\) |
… |
\(\dfrac{7}{4}\pi\) |
… |
\(\dfrac{11}{6}\pi\) |
… |
2π |
| sin x |
0 |
↘ |
\(-\dfrac{1}{2}\) |
↘ |
\(-\dfrac{\sqrt{2}}{2}\) |
↘ |
\(-\dfrac{\sqrt{3}}{2}\) |
↘ |
-1 |
↗ |
\(-\dfrac{\sqrt{3}}{2}\) |
↗ |
\(-\dfrac{\sqrt{2}}{2}\) |
↗ |
\(-\dfrac{1}{2}\) |
↗ |
0 |