|
15° |
30° |
45° |
60° |
75° |
|
165° |
150° |
135° |
120° |
105° |
| 正弦 |
\(\dfrac{\sqrt{6}-\sqrt{2}}{4}\) |
\(\dfrac{1}{2}\) |
\(\dfrac{\sqrt{2}}{2}\) |
\(\dfrac{\sqrt{3}}{2}\) |
\(\dfrac{\sqrt{6}+\sqrt{2}}{4}\) |
問題 1
| a= ① |
b= |
c= |
比 ② |
| \(\sqrt{6}\) |
2 |
\(\sqrt{3}+1\) |
\(2\sqrt{2}\) |
| sin A= |
sin B= ③ |
sin C= ④ |
|
| \(\dfrac{\sqrt{3}}{2}\) |
\(\dfrac{1}{\sqrt{2}}\) |
\(\dfrac{\sqrt{6}+\sqrt{2}}{4}\) |
1 |
| A= |
B= ⑤ |
C= ⑥ |
|
| 60° |
45° |
75° |
|
①
\(a^2=b^2+c^2-2bc\cos A\)
②
\(\dfrac{a}{\sin A}\)
③ ④ 比例計算
③ ④ 正弦表
c が最も長い辺なので，C が最も大きい角である。
問題 2
| a= ① |
b= |
c= |
比 ② |
| \(2\sqrt{2}\) |
2 |
\(\sqrt{6}+\sqrt{2}\) |
4 |
| sin A= |
sin B= ③ |
sin C= ④ |
|
| \(\dfrac{\sqrt{2}}{2}\) |
\(\dfrac{1}{2}\) |
\(\dfrac{\sqrt{6}+\sqrt{2}}{4}\) |
1 |
| A= |
B= ⑤ |
C= ⑥ |
|
| 45° |
30° |
105° |
|
①
\(a^2=b^2+c^2-2bc\cos A\)
②
\(\dfrac{a}{\sin A}\)
③ ④ 比例計算
③ ④ 正弦表
c が最も長い辺なので，C が最も大きい角である。