三角比 2

15° 30° 45° 60° 75°
165° 150° 135° 120° 105°
正弦 \(\dfrac{\sqrt{6}-\sqrt{2}}{4}\) \(\dfrac{1}{2}\) \(\dfrac{\sqrt{2}}{2}\) \(\dfrac{\sqrt{3}}{2}\) \(\dfrac{\sqrt{6}+\sqrt{2}}{4}\)

問題 3
a= b= c= ⑥ 比 ①
\(\sqrt{6}\) 2 \(\sqrt{3}+ 1\) \(2\sqrt{2}\)
\(\sqrt{6}\) 2 \(\sqrt{3}- 1\)
sin A= ② sin B= sin C= ⑤
\(\dfrac{\sqrt{3}}{2}\) \(\dfrac{1}{\sqrt{2}}\) \(\dfrac{\sqrt{6}+\sqrt{2}}{4}\) 1
\(\dfrac{\sqrt{3}}{2}\) \(\dfrac{1}{\sqrt{2}}\) \(\dfrac{\sqrt{6}-\sqrt{2}}{4}\)
A= ③ B= C= ④
60° 45° 75°
120° 45° 15°

問題 4
a= ⑥ b= c= 比 ①
\(\sqrt{3}+1\) 2 \(\sqrt{2}\) \(2\sqrt{2}\)
\(\sqrt{3}-1\) 2 \(\sqrt{2}\)
sin A= ⑤ sin B= ② sin C=
\(\dfrac{\sqrt{6}+\sqrt{2}}{4}\) \(\dfrac{1}{\sqrt{2}}\) \(\dfrac{1}{2}\) 1
\(\dfrac{\sqrt{6}-\sqrt{2}}{4}\) \(\dfrac{1}{\sqrt{2}}\) \(\dfrac{1}{2}\)
A= ④ B= ③ C=
75° 45° 30°
15° 135° 30°

つづく